131124324225535 has 8 divisors (see below), whose sum is σ = 158228234820720. Its totient is φ = 104313428880384.

The previous prime is 131124324225533. The next prime is 131124324225541. The reversal of 131124324225535 is 535522423421131.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 131124324225535 - 2¹ = 131124324225533 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 131124324225491 and 131124324225500.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (131124324225533) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 73253811522 + ... + 73253813311.

It is an arithmetic number, because the mean of its divisors is an integer number (19778529352590).

Almost surely, 2^{131124324225535} is an apocalyptic number.

131124324225535 is a deficient number, since it is larger than the sum of its proper divisors (27103910595185).

131124324225535 is a wasteful number, since it uses less digits than its factorization.

131124324225535 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 146507625017.

The product of its digits is 864000, while the sum is 43.

Adding to 131124324225535 its reverse (535522423421131), we get a palindrome (666646747646666).

The spelling of 131124324225535 in words is "one hundred thirty-one trillion, one hundred twenty-four billion, three hundred twenty-four million, two hundred twenty-five thousand, five hundred thirty-five".