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13112433550204 = 224179953863111
BaseRepresentation
bin1011111011001111100111…
…1100011010001101111100
31201102112111001001122221121
42332303321330122031330
53204313230442101304
643515434021440324
72522225220121402
oct276637174321574
951375431048847
1013112433550204
1141a5a5199811a
12157933b5700a4
137416603b9b51
143349064bd472
1517b140231554
hexbecf9f1a37c

13112433550204 has 12 divisors (see below), whose sum is σ = 23506435754928. Its totient is φ = 6396309048800.

The previous prime is 13112433550133. The next prime is 13112433550291. The reversal of 13112433550204 is 40205533421131.

It is a self number, because there is not a number n which added to its sum of digits gives 13112433550204.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 39976931392 + ... + 39976931719.

It is an arithmetic number, because the mean of its divisors is an integer number (1958869646244).

Almost surely, 213112433550204 is an apocalyptic number.

It is an amenable number.

13112433550204 is a deficient number, since it is larger than the sum of its proper divisors (10394002204724).

13112433550204 is a wasteful number, since it uses less digits than its factorization.

13112433550204 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 79953863156 (or 79953863154 counting only the distinct ones).

The product of its (nonzero) digits is 43200, while the sum is 34.

Adding to 13112433550204 its reverse (40205533421131), we get a palindrome (53317966971335).

The spelling of 13112433550204 in words is "thirteen trillion, one hundred twelve billion, four hundred thirty-three million, five hundred fifty thousand, two hundred four".

Divisors: 1 2 4 41 82 164 79953863111 159907726222 319815452444 3278108387551 6556216775102 13112433550204