Base | Representation |
---|---|
bin | 11000001111110000011100… |
… | …11110110100000111000111 |
3 | 20222210010222210101021112212 |
4 | 30013320032132310013013 |
5 | 23442030144021040320 |
6 | 305221534052334035 |
7 | 14142044632351313 |
oct | 1407701636640707 |
9 | 228703883337485 |
10 | 53317966971335 |
11 | 15a970283a4600 |
12 | 5b9146731431b |
13 | 2399b2a4b9661 |
14 | d24863912b43 |
15 | 626dc90949c5 |
hex | 307e0e7b41c7 |
53317966971335 has 48 divisors (see below), whose sum is σ = 74030566740480. Its totient is φ = 36734675313600.
The previous prime is 53317966971307. The next prime is 53317966971341.
53317966971335 is nontrivially palindromic in base 10.
It is not a de Polignac number, because 53317966971335 - 214 = 53317966954951 is a prime.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 547009814 + ... + 547107276.
It is an arithmetic number, because the mean of its divisors is an integer number (1542303473760).
Almost surely, 253317966971335 is an apocalyptic number.
53317966971335 is a gapful number since it is divisible by the number (55) formed by its first and last digit.
53317966971335 is a deficient number, since it is larger than the sum of its proper divisors (20712599769145).
53317966971335 is a wasteful number, since it uses less digits than its factorization.
53317966971335 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 145100 (or 145089 counting only the distinct ones).
The product of its digits is 289340100, while the sum is 68.
The spelling of 53317966971335 in words is "fifty-three trillion, three hundred seventeen billion, nine hundred sixty-six million, nine hundred seventy-one thousand, three hundred thirty-five".
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