131124401 has 2 divisors, whose sum is σ = 131124402. Its totient is φ = 131124400.

The previous prime is 131124397. The next prime is 131124419. The reversal of 131124401 is 104421131.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 115004176 + 16120225 = 10724^2 + 4015^2 .

It is a cyclic number.

It is not a de Polignac number, because 131124401 - 2² = 131124397 is a prime.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 131124401.

It is not a weakly prime, because it can be changed into another prime (131124421) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65562200 + 65562201.

It is an arithmetic number, because the mean of its divisors is an integer number (65562201).

Almost surely, 2^131124401 is an apocalyptic number.

It is an amenable number.

131124401 is a deficient number, since it is larger than the sum of its proper divisors (1).

131124401 is an equidigital number, since it uses as much as digits as its factorization.

131124401 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 96, while the sum is 17.

The square root of 131124401 is about 11450.9563356080. The cubic root of 131124401 is about 508.0360208095.

Adding to 131124401 its reverse (104421131), we get a palindrome (235545532).

The spelling of 131124401 in words is "one hundred thirty-one million, one hundred twenty-four thousand, four hundred one".