Base | Representation |
---|---|
bin | 10011000101001100010… |
… | …000001111111010000001 |
3 | 11122100112212120202222100 |
4 | 103011030100033322001 |
5 | 132440412023300103 |
6 | 2442213301101013 |
7 | 163506600050160 |
oct | 23051420177201 |
9 | 4570485522870 |
10 | 1311244353153 |
11 | 466106287139 |
12 | 1921650b7769 |
13 | 9685a838147 |
14 | 47670aa53d7 |
15 | 241961805a3 |
hex | 1314c40fe81 |
1311244353153 has 24 divisors (see below), whose sum is σ = 2164649760000. Its totient is φ = 749263135104.
The previous prime is 1311244353131. The next prime is 1311244353163. The reversal of 1311244353153 is 3513534421131.
1311244353153 is a `hidden beast` number, since 1 + 3 + 1 + 12 + 443 + 53 + 153 = 666.
It is not a de Polignac number, because 1311244353153 - 210 = 1311244352129 is a prime.
It is not an unprimeable number, because it can be changed into a prime (1311244353103) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 2398153 + ... + 2893721.
It is an arithmetic number, because the mean of its divisors is an integer number (90193740000).
Almost surely, 21311244353153 is an apocalyptic number.
It is an amenable number.
1311244353153 is a deficient number, since it is larger than the sum of its proper divisors (853405406847).
1311244353153 is a wasteful number, since it uses less digits than its factorization.
1311244353153 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 537581 (or 537578 counting only the distinct ones).
The product of its digits is 64800, while the sum is 36.
Adding to 1311244353153 its reverse (3513534421131), we get a palindrome (4824778774284).
The spelling of 1311244353153 in words is "one trillion, three hundred eleven billion, two hundred forty-four million, three hundred fifty-three thousand, one hundred fifty-three".
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