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13112511354134 = 217252697430499
BaseRepresentation
bin1011111011001111111010…
…0101001101010100010110
31201102112200110110111212122
42332303332211031110112
53204313410401313014
643515445441215542
72522230153340123
oct276637645152426
951375613414778
1013112511354134
1141a5a918a9395
1215793616315b2
1374167355b78a
1433491297374a
1517b146e9e58e
hexbecfe94d516

13112511354134 has 24 divisors (see below), whose sum is σ = 20894256369000. Its totient is φ = 6170462149376.

The previous prime is 13112511354119. The next prime is 13112511354167. The reversal of 13112511354134 is 43145311521131.

It is a super-3 number, since 3×131125113541343 (a number of 40 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 13112511354094 and 13112511354103.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 30243617 + ... + 30674115.

It is an arithmetic number, because the mean of its divisors is an integer number (870594015375).

Almost surely, 213112511354134 is an apocalyptic number.

13112511354134 is a deficient number, since it is larger than the sum of its proper divisors (7781745014866).

13112511354134 is a wasteful number, since it uses less digits than its factorization.

13112511354134 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 483232 (or 483215 counting only the distinct ones).

The product of its digits is 21600, while the sum is 35.

Adding to 13112511354134 its reverse (43145311521131), we get a palindrome (56257822875265).

The spelling of 13112511354134 in words is "thirteen trillion, one hundred twelve billion, five hundred eleven million, three hundred fifty-four thousand, one hundred thirty-four".

Divisors: 1 2 17 34 289 578 52697 105394 430499 860998 895849 1791698 7318483 14636966 15229433 30458866 124414211 248828422 22686005803 45372011606 385662098651 771324197302 6556255677067 13112511354134