Base | Representation |
---|---|
bin | 1011111011001111111010… |
… | …0101001101010100010110 |
3 | 1201102112200110110111212122 |
4 | 2332303332211031110112 |
5 | 3204313410401313014 |
6 | 43515445441215542 |
7 | 2522230153340123 |
oct | 276637645152426 |
9 | 51375613414778 |
10 | 13112511354134 |
11 | 41a5a918a9395 |
12 | 15793616315b2 |
13 | 74167355b78a |
14 | 33491297374a |
15 | 17b146e9e58e |
hex | becfe94d516 |
13112511354134 has 24 divisors (see below), whose sum is σ = 20894256369000. Its totient is φ = 6170462149376.
The previous prime is 13112511354119. The next prime is 13112511354167. The reversal of 13112511354134 is 43145311521131.
It is a super-3 number, since 3×131125113541343 (a number of 40 digits) contains 333 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 13112511354094 and 13112511354103.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 30243617 + ... + 30674115.
It is an arithmetic number, because the mean of its divisors is an integer number (870594015375).
Almost surely, 213112511354134 is an apocalyptic number.
13112511354134 is a deficient number, since it is larger than the sum of its proper divisors (7781745014866).
13112511354134 is a wasteful number, since it uses less digits than its factorization.
13112511354134 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 483232 (or 483215 counting only the distinct ones).
The product of its digits is 21600, while the sum is 35.
Adding to 13112511354134 its reverse (43145311521131), we get a palindrome (56257822875265).
The spelling of 13112511354134 in words is "thirteen trillion, one hundred twelve billion, five hundred eleven million, three hundred fifty-four thousand, one hundred thirty-four".
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