13112512011035 has 4 divisors (see below), whose sum is σ = 15735014413248. Its totient is φ = 10490009608824.

The previous prime is 13112512011019. The next prime is 13112512011037. The reversal of 13112512011035 is 53011021521131.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13112512011035 - 2⁴ = 13112512011019 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13112512010995 and 13112512011013.

It is not an unprimeable number, because it can be changed into a prime (13112512011037) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1311251201099 + ... + 1311251201108.

It is an arithmetic number, because the mean of its divisors is an integer number (3933753603312).

Almost surely, 2^{13112512011035} is an apocalyptic number.

13112512011035 is a deficient number, since it is larger than the sum of its proper divisors (2622502402213).

13112512011035 is an equidigital number, since it uses as much as digits as its factorization.

13112512011035 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2622502402212.

The product of its (nonzero) digits is 900, while the sum is 26.

Adding to 13112512011035 its reverse (53011021521131), we get a palindrome (66123533532166).

The spelling of 13112512011035 in words is "thirteen trillion, one hundred twelve billion, five hundred twelve million, eleven thousand, thirty-five".