1311300103121 has 2 divisors, whose sum is σ = 1311300103122. Its totient is φ = 1311300103120.

The previous prime is 1311300103079. The next prime is 1311300103123. The reversal of 1311300103121 is 1213010031131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 724092076096 + 587208027025 = 850936^2 + 766295^2 .

It is a cyclic number.

It is not a de Polignac number, because 1311300103121 - 2²⁶ = 1311232994257 is a prime.

Together with 1311300103123, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 1311300103121.

It is not a weakly prime, because it can be changed into another prime (1311300103123) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655650051560 + 655650051561.

It is an arithmetic number, because the mean of its divisors is an integer number (655650051561).

Almost surely, 2^{1311300103121} is an apocalyptic number.

It is an amenable number.

1311300103121 is a deficient number, since it is larger than the sum of its proper divisors (1).

1311300103121 is an equidigital number, since it uses as much as digits as its factorization.

1311300103121 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 54, while the sum is 17.

Adding to 1311300103121 its reverse (1213010031131), we get a palindrome (2524310134252).

The spelling of 1311300103121 in words is "one trillion, three hundred eleven billion, three hundred million, one hundred three thousand, one hundred twenty-one".