Base | Representation |
---|---|
bin | 10011000101001111100… |
… | …101011100100000011000 |
3 | 11122100200202202012021121 |
4 | 103011033211130200120 |
5 | 132441020330211212 |
6 | 2442223015015024 |
7 | 163511146100566 |
oct | 23051745344030 |
9 | 4570622665247 |
10 | 1311300241432 |
11 | 4661348898a5 |
12 | 19217b96a474 |
13 | 968692a572c |
14 | 47678292a36 |
15 | 2419b01ed07 |
hex | 1314f95c818 |
1311300241432 has 16 divisors (see below), whose sum is σ = 2458790279640. Its totient is φ = 655622833536.
The previous prime is 1311300241399. The next prime is 1311300241453. The reversal of 1311300241432 is 2341420031131.
It is a junction number, because it is equal to n+sod(n) for n = 1311300241397 and 1311300241406.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3205938 + ... + 3591745.
Almost surely, 21311300241432 is an apocalyptic number.
It is an amenable number.
1311300241432 is a deficient number, since it is larger than the sum of its proper divisors (1147490038208).
1311300241432 is a wasteful number, since it uses less digits than its factorization.
1311300241432 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6821802 (or 6821798 counting only the distinct ones).
The product of its (nonzero) digits is 1728, while the sum is 25.
Adding to 1311300241432 its reverse (2341420031131), we get a palindrome (3652720272563).
The spelling of 1311300241432 in words is "one trillion, three hundred eleven billion, three hundred million, two hundred forty-one thousand, four hundred thirty-two".
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