131130211333 has 4 divisors (see below), whose sum is σ = 143051139648. Its totient is φ = 119209283020.

The previous prime is 131130211321. The next prime is 131130211339. The reversal of 131130211333 is 333112031131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-131130211333 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (131130211339) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5960464141 + ... + 5960464162.

It is an arithmetic number, because the mean of its divisors is an integer number (35762784912).

Almost surely, 2^131130211333 is an apocalyptic number.

It is an amenable number.

131130211333 is a deficient number, since it is larger than the sum of its proper divisors (11920928315).

131130211333 is a wasteful number, since it uses less digits than its factorization.

131130211333 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 11920928314.

The product of its (nonzero) digits is 486, while the sum is 22.

Adding to 131130211333 its reverse (333112031131), we get a palindrome (464242242464).

The spelling of 131130211333 in words is "one hundred thirty-one billion, one hundred thirty million, two hundred eleven thousand, three hundred thirty-three".