Base | Representation |
---|---|
bin | 1011111011010001110110… |
… | …1100010110101111000111 |
3 | 1201102121000211122012101011 |
4 | 2332310131230112233013 |
5 | 3204320443012241130 |
6 | 43520013324543051 |
7 | 2522246122105456 |
oct | 276643554265707 |
9 | 51377024565334 |
10 | 13113033321415 |
11 | 41a622a4aa105 |
12 | 15794883b1a87 |
13 | 741727735561 |
14 | 334962006b9d |
15 | 17b177c0652a |
hex | bed1db16bc7 |
13113033321415 has 8 divisors (see below), whose sum is σ = 15970500284400. Its totient is φ = 10333853124672.
The previous prime is 13113033321337. The next prime is 13113033321439. The reversal of 13113033321415 is 51412333031131.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 13113033321415 - 231 = 13110885837767 is a prime.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 19571691190 + ... + 19571691859.
It is an arithmetic number, because the mean of its divisors is an integer number (1996312535550).
Almost surely, 213113033321415 is an apocalyptic number.
13113033321415 is a deficient number, since it is larger than the sum of its proper divisors (2857466962985).
13113033321415 is an equidigital number, since it uses as much as digits as its factorization.
13113033321415 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 39143383121.
The product of its (nonzero) digits is 9720, while the sum is 31.
Adding to 13113033321415 its reverse (51412333031131), we get a palindrome (64525366352546).
The spelling of 13113033321415 in words is "thirteen trillion, one hundred thirteen billion, thirty-three million, three hundred twenty-one thousand, four hundred fifteen".
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