13113101123100 has 432 divisors, whose sum is σ = 45088816631040. Its totient is φ = 3161246054400.

The previous prime is 13113101123099. The next prime is 13113101123141. The reversal of 13113101123100 is 132110131131.

13113101123100 is a `hidden beast` number, since 1 + 31 + 1 + 310 + 1 + 12 + 310 + 0 = 666.

It is a super-2 number, since 2×13113101123100² (a number of 27 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (18).

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 143 ways as a sum of consecutive naturals, for example, 2267522809 + ... + 2267528591.

It is an arithmetic number, because the mean of its divisors is an integer number (104372260720).

Almost surely, 2^{13113101123100} is an apocalyptic number.

13113101123100 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 13113101123100, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (22544408315520).

13113101123100 is an abundant number, since it is smaller than the sum of its proper divisors (31975715507940).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13113101123100 is a wasteful number, since it uses less digits than its factorization.

13113101123100 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 7050 (or 7040 counting only the distinct ones).

The product of its (nonzero) digits is 54, while the sum is 18.

Adding to 13113101123100 its reverse (132110131131), we get a palindrome (13245211254231).

The spelling of 13113101123100 in words is "thirteen trillion, one hundred thirteen billion, one hundred one million, one hundred twenty-three thousand, one hundred".