Base | Representation |
---|---|
bin | 11000011011001101… |
… | …00000101111110111 |
3 | 1020211212121120021122 |
4 | 30031212200233313 |
5 | 203323423220203 |
6 | 10005111134155 |
7 | 642645344021 |
oct | 141546405767 |
9 | 36755546248 |
10 | 13113101303 |
11 | 561a005105 |
12 | 265b67435b |
13 | 130c951853 |
14 | 8c57ab011 |
15 | 51b343538 |
hex | 30d9a0bf7 |
13113101303 has 8 divisors (see below), whose sum is σ = 13579721280. Its totient is φ = 12647444320.
The previous prime is 13113101293. The next prime is 13113101329. The reversal of 13113101303 is 30310131131.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 13113101303 - 210 = 13113100279 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13113101333) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 212975 + ... + 267552.
It is an arithmetic number, because the mean of its divisors is an integer number (1697465160).
Almost surely, 213113101303 is an apocalyptic number.
13113101303 is a deficient number, since it is larger than the sum of its proper divisors (466619977).
13113101303 is an equidigital number, since it uses as much as digits as its factorization.
13113101303 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 481497.
The product of its (nonzero) digits is 81, while the sum is 17.
Adding to 13113101303 its reverse (30310131131), we get a palindrome (43423232434).
The spelling of 13113101303 in words is "thirteen billion, one hundred thirteen million, one hundred one thousand, three hundred three".
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