1311310203330 has 64 divisors (see below), whose sum is σ = 3180302673408. Its totient is φ = 346000097280.

The previous prime is 1311310203283. The next prime is 1311310203361. The reversal of 1311310203330 is 333020131131.

It is a junction number, because it is equal to n+sod(n) for n = 1311310203297 and 1311310203306.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 13550215 + ... + 13646645.

It is an arithmetic number, because the mean of its divisors is an integer number (49692229272).

Almost surely, 2^{1311310203330} is an apocalyptic number.

1311310203330 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

1311310203330 is an abundant number, since it is smaller than the sum of its proper divisors (1868992470078).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1311310203330 is a wasteful number, since it uses less digits than its factorization.

1311310203330 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 101211.

The product of its (nonzero) digits is 486, while the sum is 21.

Adding to 1311310203330 its reverse (333020131131), we get a palindrome (1644330334461).

The spelling of 1311310203330 in words is "one trillion, three hundred eleven billion, three hundred ten million, two hundred three thousand, three hundred thirty".