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131131031 is a prime number
BaseRepresentation
bin1111101000011…
…10011010010111
3100010202010221212
413310032122113
5232032143111
621002332035
73151411133
oct764163227
9303663855
10131131031
1168024759
1237aba01b
1321223535
14135b63c3
15b7a398b
hex7d0e697

131131031 has 2 divisors, whose sum is σ = 131131032. Its totient is φ = 131131030.

The previous prime is 131131009. The next prime is 131131043. The reversal of 131131031 is 130131131.

It is a happy number.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 131131031 - 210 = 131130007 is a prime.

It is a super-2 number, since 2×1311310312 = 34390694582245922, which contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 131130997 and 131131015.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (131131001) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65565515 + 65565516.

It is an arithmetic number, because the mean of its divisors is an integer number (65565516).

Almost surely, 2131131031 is an apocalyptic number.

131131031 is a deficient number, since it is larger than the sum of its proper divisors (1).

131131031 is an equidigital number, since it uses as much as digits as its factorization.

131131031 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 27, while the sum is 14.

The square root of 131131031 is about 11451.2458274198. The cubic root of 131131031 is about 508.0445832180.

Adding to 131131031 its reverse (130131131), we get a palindrome (261262162).

The spelling of 131131031 in words is "one hundred thirty-one million, one hundred thirty-one thousand, thirty-one".