13113111120223 has 4 divisors (see below), whose sum is σ = 13114863983088. Its totient is φ = 13111358257360.

The previous prime is 13113111120149. The next prime is 13113111120227. The reversal of 13113111120223 is 32202111131131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13113111120223 is a prime.

It is a super-2 number, since 2×13113111120223² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13113111120194 and 13113111120203.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13113111120227) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 876420211 + ... + 876435172.

It is an arithmetic number, because the mean of its divisors is an integer number (3278715995772).

Almost surely, 2^{13113111120223} is an apocalyptic number.

13113111120223 is a deficient number, since it is larger than the sum of its proper divisors (1752862865).

13113111120223 is an equidigital number, since it uses as much as digits as its factorization.

13113111120223 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1752862864.

The product of its (nonzero) digits is 216, while the sum is 22.

Adding to 13113111120223 its reverse (32202111131131), we get a palindrome (45315222251354).

The spelling of 13113111120223 in words is "thirteen trillion, one hundred thirteen billion, one hundred eleven million, one hundred twenty thousand, two hundred twenty-three".