13113112013 has 2 divisors, whose sum is σ = 13113112014. Its totient is φ = 13113112012.

The previous prime is 13113112009. The next prime is 13113112037. The reversal of 13113112013 is 31021131131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 10289464969 + 2823647044 = 101437^2 + 53138^2 .

It is an emirp because it is prime and its reverse (31021131131) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13113112013 - 2² = 13113112009 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 13113111982 and 13113112000.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13113112213) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6556556006 + 6556556007.

It is an arithmetic number, because the mean of its divisors is an integer number (6556556007).

Almost surely, 2^13113112013 is an apocalyptic number.

It is an amenable number.

13113112013 is a deficient number, since it is larger than the sum of its proper divisors (1).

13113112013 is an equidigital number, since it uses as much as digits as its factorization.

13113112013 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 54, while the sum is 17.

Adding to 13113112013 its reverse (31021131131), we get a palindrome (44134243144).

The spelling of 13113112013 in words is "thirteen billion, one hundred thirteen million, one hundred twelve thousand, thirteen".