Base | Representation |
---|---|
bin | 10011000101010000001… |
… | …111101001001110000011 |
3 | 11122100201112120012122212 |
4 | 103011100033221032003 |
5 | 132441031143203210 |
6 | 2442224052052335 |
7 | 163511342112641 |
oct | 23052017511603 |
9 | 4570645505585 |
10 | 1311311303555 |
11 | 466140054a50 |
12 | 1921836040ab |
13 | 9686b679876 |
14 | 47679932191 |
15 | 2419bea7805 |
hex | 131503e9383 |
1311311303555 has 8 divisors (see below), whose sum is σ = 1716625706544. Its totient is φ = 953680948000.
The previous prime is 1311311303531. The next prime is 1311311303569. The reversal of 1311311303555 is 5553031131131.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a de Polignac number, because none of the positive numbers 2k-1311311303555 is a prime.
It is a super-2 number, since 2×13113113035552 (a number of 25 digits) contains 22 as substring.
It is a Duffinian number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 11921011796 + ... + 11921011905.
It is an arithmetic number, because the mean of its divisors is an integer number (214578213318).
Almost surely, 21311311303555 is an apocalyptic number.
1311311303555 is a deficient number, since it is larger than the sum of its proper divisors (405314402989).
1311311303555 is a wasteful number, since it uses less digits than its factorization.
1311311303555 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 23842023717.
The product of its (nonzero) digits is 10125, while the sum is 32.
Adding to 1311311303555 its reverse (5553031131131), we get a palindrome (6864342434686).
The spelling of 1311311303555 in words is "one trillion, three hundred eleven billion, three hundred eleven million, three hundred three thousand, five hundred fifty-five".
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