Base | Representation |
---|---|
bin | 11101110100001101011101… |
… | …110110100101001001111110 |
3 | 122012022000121021002102121020 |
4 | 131310031131312211021332 |
5 | 114141423220100300410 |
6 | 1142520503520045010 |
7 | 36422626621345545 |
oct | 3564153566451176 |
9 | 565260537072536 |
10 | 131131221103230 |
11 | 38867490802177 |
12 | 1285a138763766 |
13 | 582280c6c832a |
14 | 2454adbd3515c |
15 | 1026055e7ba70 |
hex | 77435dda527e |
131131221103230 has 32 divisors (see below), whose sum is σ = 314724251615904. Its totient is φ = 34967289964416.
The previous prime is 131131221103199. The next prime is 131131221103243. The reversal of 131131221103230 is 32301122131131.
It is a self number, because there is not a number n which added to its sum of digits gives 131131221103230.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 63698869 + ... + 65725248.
It is an arithmetic number, because the mean of its divisors is an integer number (9835132862997).
Almost surely, 2131131221103230 is an apocalyptic number.
131131221103230 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
131131221103230 is an abundant number, since it is smaller than the sum of its proper divisors (183593030512674).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
131131221103230 is a wasteful number, since it uses less digits than its factorization.
131131221103230 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 129457900.
The product of its (nonzero) digits is 648, while the sum is 24.
Adding to 131131221103230 its reverse (32301122131131), we get a palindrome (163432343234361).
The spelling of 131131221103230 in words is "one hundred thirty-one trillion, one hundred thirty-one billion, two hundred twenty-one million, one hundred three thousand, two hundred thirty".
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