1311313011322 has 4 divisors (see below), whose sum is σ = 1966969516986. Its totient is φ = 655656505660.

The previous prime is 1311313011319. The next prime is 1311313011329. The reversal of 1311313011322 is 2231103131131.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 963497333241 + 347815678081 = 981579^2 + 589759^2 .

It is a junction number, because it is equal to n+sod(n) for n = 1311313011293 and 1311313011302.

It is not an unprimeable number, because it can be changed into a prime (1311313011329) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 327828252829 + ... + 327828252832.

Almost surely, 2^{1311313011322} is an apocalyptic number.

1311313011322 is a deficient number, since it is larger than the sum of its proper divisors (655656505664).

1311313011322 is an equidigital number, since it uses as much as digits as its factorization.

1311313011322 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 655656505663.

The product of its (nonzero) digits is 324, while the sum is 22.

Adding to 1311313011322 its reverse (2231103131131), we get a palindrome (3542416142453).

The spelling of 1311313011322 in words is "one trillion, three hundred eleven billion, three hundred thirteen million, eleven thousand, three hundred twenty-two".