Base | Representation |
---|---|
bin | 111101000100000001… |
… | …0010010100000001101 |
3 | 110112110202201021100220 |
4 | 1322020002102200031 |
5 | 4122024104222313 |
6 | 140124011141553 |
7 | 12321361555236 |
oct | 1721002224015 |
9 | 415422637326 |
10 | 131131320333 |
11 | 50681236912 |
12 | 214b77448b9 |
13 | c49a3a0450 |
14 | 64bd83c08d |
15 | 3627334823 |
hex | 1e8809280d |
131131320333 has 8 divisors (see below), whose sum is σ = 188291126688. Its totient is φ = 80696197104.
The previous prime is 131131320323. The next prime is 131131320347. The reversal of 131131320333 is 333023131131.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 131131320333 - 25 = 131131320301 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (131131320323) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1681170735 + ... + 1681170812.
It is an arithmetic number, because the mean of its divisors is an integer number (23536390836).
Almost surely, 2131131320333 is an apocalyptic number.
131131320333 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
It is an amenable number.
131131320333 is a deficient number, since it is larger than the sum of its proper divisors (57159806355).
131131320333 is a wasteful number, since it uses less digits than its factorization.
131131320333 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 3362341563.
The product of its (nonzero) digits is 1458, while the sum is 24.
Adding to 131131320333 its reverse (333023131131), we get a palindrome (464154451464).
The spelling of 131131320333 in words is "one hundred thirty-one billion, one hundred thirty-one million, three hundred twenty thousand, three hundred thirty-three".
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