1311314131130 has 16 divisors (see below), whose sum is σ = 2360490577704. Its totient is φ = 524497843200.

The previous prime is 1311314131117. The next prime is 1311314131139. The reversal of 1311314131130 is 311314131131.

It can be written as a sum of positive squares in 4 ways, for example, as 1185073909321 + 126240221809 = 1088611^2 + 355303^2 .

It is a junction number, because it is equal to n+sod(n) for n = 1311314131096 and 1311314131105.

It is not an unprimeable number, because it can be changed into a prime (1311314131139) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 3277571 + ... + 3655830.

Almost surely, 2^{1311314131130} is an apocalyptic number.

1311314131130 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

1311314131130 is a deficient number, since it is larger than the sum of its proper divisors (1049176446574).

1311314131130 is a wasteful number, since it uses less digits than its factorization.

1311314131130 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6952321.

The product of its (nonzero) digits is 324, while the sum is 23.

Adding to 1311314131130 its reverse (311314131131), we get a palindrome (1622628262261).

Subtracting from 1311314131130 its reverse (311314131131), we obtain a palindrome (999999999999).

The spelling of 1311314131130 in words is "one trillion, three hundred eleven billion, three hundred fourteen million, one hundred thirty-one thousand, one hundred thirty".