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1311314221141 is a prime number
BaseRepresentation
bin10011000101010000011…
…010110001100001010101
311122100201202001102211121
4103011100122301201111
5132441032420034031
62442224234403541
7163511405654011
oct23052032614125
94570652042747
101311314221141
11466141767a81
121921845905b1
139686c15b852
144767a091541
152419c382011
hex131506b1855

1311314221141 has 2 divisors, whose sum is σ = 1311314221142. Its totient is φ = 1311314221140.

The previous prime is 1311314221111. The next prime is 1311314221159. The reversal of 1311314221141 is 1411224131131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1095015744900 + 216298476241 = 1046430^2 + 465079^2 .

It is a cyclic number.

It is not a de Polignac number, because 1311314221141 - 27 = 1311314221013 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1311314221111) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655657110570 + 655657110571.

It is an arithmetic number, because the mean of its divisors is an integer number (655657110571).

Almost surely, 21311314221141 is an apocalyptic number.

It is an amenable number.

1311314221141 is a deficient number, since it is larger than the sum of its proper divisors (1).

1311314221141 is an equidigital number, since it uses as much as digits as its factorization.

1311314221141 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 576, while the sum is 25.

Adding to 1311314221141 its reverse (1411224131131), we get a palindrome (2722538352272).

The spelling of 1311314221141 in words is "one trillion, three hundred eleven billion, three hundred fourteen million, two hundred twenty-one thousand, one hundred forty-one".