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1311320043310 = 25791659898789
BaseRepresentation
bin10011000101010000110…
…000111110111100101110
311122100202011000020100111
4103011100300332330232
5132441040412341220
62442225003250234
7163511506313164
oct23052060767456
94570664006314
101311320043310
11466144a84292
1219218651997a
1396870419914
144767ab69234
152419cb3215a
hex13150c3ef2e

1311320043310 has 16 divisors (see below), whose sum is σ = 2390254257600. Its totient is φ = 517888421856.

The previous prime is 1311320043259. The next prime is 1311320043311. The reversal of 1311320043310 is 133400231131.

It is a super-2 number, since 2×13113200433102 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1311320043311) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 829948605 + ... + 829950184.

It is an arithmetic number, because the mean of its divisors is an integer number (149390891100).

Almost surely, 21311320043310 is an apocalyptic number.

1311320043310 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

1311320043310 is a deficient number, since it is larger than the sum of its proper divisors (1078934214290).

1311320043310 is a wasteful number, since it uses less digits than its factorization.

1311320043310 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1659898875.

The product of its (nonzero) digits is 648, while the sum is 22.

Adding to 1311320043310 its reverse (133400231131), we get a palindrome (1444720274441).

The spelling of 1311320043310 in words is "one trillion, three hundred eleven billion, three hundred twenty million, forty-three thousand, three hundred ten".

Divisors: 1 2 5 10 79 158 395 790 1659898789 3319797578 8299493945 16598987890 131132004331 262264008662 655660021655 1311320043310