Base | Representation |
---|---|
bin | 10011000101010000110… |
… | …001001111100010000101 |
3 | 11122100202011010200112022 |
4 | 103011100301033202011 |
5 | 132441040422024422 |
6 | 2442225004532525 |
7 | 163511510015213 |
oct | 23052061174205 |
9 | 4570664120468 |
10 | 1311320111237 |
11 | 466145020324 |
12 | 192186551145 |
13 | 96870441806 |
14 | 4767ab85cb3 |
15 | 2419cb47342 |
hex | 13150c4f885 |
1311320111237 has 2 divisors, whose sum is σ = 1311320111238. Its totient is φ = 1311320111236.
The previous prime is 1311320111209. The next prime is 1311320111243. The reversal of 1311320111237 is 7321110231131.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 829175969281 + 482144141956 = 910591^2 + 694366^2 .
It is a cyclic number.
It is not a de Polignac number, because 1311320111237 - 26 = 1311320111173 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1311320111207) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655660055618 + 655660055619.
It is an arithmetic number, because the mean of its divisors is an integer number (655660055619).
Almost surely, 21311320111237 is an apocalyptic number.
It is an amenable number.
1311320111237 is a deficient number, since it is larger than the sum of its proper divisors (1).
1311320111237 is an equidigital number, since it uses as much as digits as its factorization.
1311320111237 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 756, while the sum is 26.
Adding to 1311320111237 its reverse (7321110231131), we get a palindrome (8632430342368).
The spelling of 1311320111237 in words is "one trillion, three hundred eleven billion, three hundred twenty million, one hundred eleven thousand, two hundred thirty-seven".
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