131132023000421 has 4 divisors (see below), whose sum is σ = 131139134685600. Its totient is φ = 131124911315244.

The previous prime is 131132023000337. The next prime is 131132023000423. The reversal of 131132023000421 is 124000320231131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 131132023000421 - 2⁴² = 126733976489317 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (131132023000423) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3555814931 + ... + 3555851808.

It is an arithmetic number, because the mean of its divisors is an integer number (32784783671400).

Almost surely, 2^{131132023000421} is an apocalyptic number.

It is an amenable number.

131132023000421 is a deficient number, since it is larger than the sum of its proper divisors (7111685179).

131132023000421 is an equidigital number, since it uses as much as digits as its factorization.

131132023000421 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 7111685178.

The product of its (nonzero) digits is 864, while the sum is 23.

Adding to 131132023000421 its reverse (124000320231131), we get a palindrome (255132343231552).

The spelling of 131132023000421 in words is "one hundred thirty-one trillion, one hundred thirty-two billion, twenty-three million, four hundred twenty-one", and thus it is an aban number.