| Base | Representation |
|---|---|
| bin | 11000011011001101… |
| … | …11001101001100100 |
| 3 | 1020211212210202012022 |
| 4 | 30031212321221210 |
| 5 | 203323440001200 |
| 6 | 10005113242312 |
| 7 | 642646250261 |
| oct | 141546715144 |
| 9 | 36755722168 |
| 10 | 13113203300 |
| 11 | 561a0747aa |
| 12 | 265b703398 |
| 13 | 130c9890c2 |
| 14 | 8c57d6268 |
| 15 | 51b363885 |
| hex | 30d9b9a64 |
13113203300 has 144 divisors (see below), whose sum is σ = 31158005760. Its totient is φ = 4770109440.
The previous prime is 13113203291. The next prime is 13113203303. The reversal of 13113203300 is 330231131.
13113203300 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a super-2 number, since 2×131132033002 (a number of 21 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (17).
It is not an unprimeable number, because it can be changed into a prime (13113203303) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 10252061 + ... + 10253339.
It is an arithmetic number, because the mean of its divisors is an integer number (216375040).
Almost surely, 213113203300 is an apocalyptic number.
13113203300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 13113203300, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (15579002880).
13113203300 is an abundant number, since it is smaller than the sum of its proper divisors (18044802460).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13113203300 is a wasteful number, since it uses less digits than its factorization.
13113203300 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1510 (or 1503 counting only the distinct ones).
The product of its (nonzero) digits is 162, while the sum is 17.
Adding to 13113203300 its reverse (330231131), we get a palindrome (13443434431).
The spelling of 13113203300 in words is "thirteen billion, one hundred thirteen million, two hundred three thousand, three hundred".
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