131132101181 has 2 divisors, whose sum is σ = 131132101182. Its totient is φ = 131132101180.

The previous prime is 131132101159. The next prime is 131132101201. The reversal of 131132101181 is 181101231131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 119487748900 + 11644352281 = 345670^2 + 107909^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-131132101181 is a prime.

It is a super-2 number, since 2×131132101181² (a number of 23 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (131132109181) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65566050590 + 65566050591.

It is an arithmetic number, because the mean of its divisors is an integer number (65566050591).

Almost surely, 2^131132101181 is an apocalyptic number.

It is an amenable number.

131132101181 is a deficient number, since it is larger than the sum of its proper divisors (1).

131132101181 is an equidigital number, since it uses as much as digits as its factorization.

131132101181 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 144, while the sum is 23.

The spelling of 131132101181 in words is "one hundred thirty-one billion, one hundred thirty-two million, one hundred one thousand, one hundred eighty-one".