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13113211034335 = 514545918030113
BaseRepresentation
bin1011111011010010100001…
…0010010001101011011111
31201102121111020000221200011
42332310220102101223133
53204321324011044320
643520043113544051
72522253410460106
oct276645022215337
951377436027604
1013113211034335
1141a631084a495
121579517a15027
137417554b8429
1433497b86703d
1517b18860c05a
hexbed28491adf

13113211034335 has 8 divisors (see below), whose sum is σ = 15735962294640. Its totient is φ = 10490496125184.

The previous prime is 13113211034327. The next prime is 13113211034377. The reversal of 13113211034335 is 53343011231131.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 13113211034335 - 23 = 13113211034327 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 13113211034297 and 13113211034306.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 8287762 + ... + 9742351.

It is an arithmetic number, because the mean of its divisors is an integer number (1966995286830).

Almost surely, 213113211034335 is an apocalyptic number.

13113211034335 is a deficient number, since it is larger than the sum of its proper divisors (2622751260305).

13113211034335 is a wasteful number, since it uses less digits than its factorization.

13113211034335 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 18175577.

The product of its (nonzero) digits is 9720, while the sum is 31.

Adding to 13113211034335 its reverse (53343011231131), we get a palindrome (66456222265466).

The spelling of 13113211034335 in words is "thirteen trillion, one hundred thirteen billion, two hundred eleven million, thirty-four thousand, three hundred thirty-five".

Divisors: 1 5 145459 727295 18030113 90150565 2622642206867 13113211034335