13113211311101 has 4 divisors (see below), whose sum is σ = 14305321430304. Its totient is φ = 11921101191900.

The previous prime is 13113211311041. The next prime is 13113211311103. The reversal of 13113211311101 is 10111311231131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13113211311101 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13113211311103) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 596055059585 + ... + 596055059606.

It is an arithmetic number, because the mean of its divisors is an integer number (3576330357576).

Almost surely, 2^{13113211311101} is an apocalyptic number.

13113211311101 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

It is an amenable number.

13113211311101 is a deficient number, since it is larger than the sum of its proper divisors (1192110119203).

13113211311101 is a wasteful number, since it uses less digits than its factorization.

13113211311101 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1192110119202.

The product of its (nonzero) digits is 54, while the sum is 20.

Adding to 13113211311101 its reverse (10111311231131), we get a palindrome (23224522542232).

The spelling of 13113211311101 in words is "thirteen trillion, one hundred thirteen billion, two hundred eleven million, three hundred eleven thousand, one hundred one".