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131132113300 = 22521311321133
BaseRepresentation
bin111101000100000010…
…1010100000110010100
3110112110211012120010001
41322020011110012110
54122024310111200
6140124040141044
712321401400136
oct1721005240624
9415424176101
10131132113300
1150681728661
12214b7a67784
13c49a5ba366
1464bd9a7056
15362743e76a
hex1e88154194

131132113300 has 18 divisors (see below), whose sum is σ = 284556686078. Its totient is φ = 52452845280.

The previous prime is 131132113289. The next prime is 131132113337. The reversal of 131132113300 is 3311231131.

It can be written as a sum of positive squares in 3 ways, for example, as 538054416 + 130594058884 = 23196^2 + 361378^2 .

It is a super-2 number, since 2×1311321133002 (a number of 23 digits) contains 22 as substring.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 655660467 + ... + 655660666.

Almost surely, 2131132113300 is an apocalyptic number.

131132113300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

131132113300 is an abundant number, since it is smaller than the sum of its proper divisors (153424572778).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

131132113300 is a wasteful number, since it uses less digits than its factorization.

131132113300 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1311321147 (or 1311321140 counting only the distinct ones).

The product of its (nonzero) digits is 162, while the sum is 19.

Adding to 131132113300 its reverse (3311231131), we get a palindrome (134443344431).

The spelling of 131132113300 in words is "one hundred thirty-one billion, one hundred thirty-two million, one hundred thirteen thousand, three hundred".

Divisors: 1 2 4 5 10 20 25 50 100 1311321133 2622642266 5245284532 6556605665 13113211330 26226422660 32783028325 65566056650 131132113300