Base | Representation |
---|---|
bin | 111101000100000010… |
… | …1010100000110010100 |
3 | 110112110211012120010001 |
4 | 1322020011110012110 |
5 | 4122024310111200 |
6 | 140124040141044 |
7 | 12321401400136 |
oct | 1721005240624 |
9 | 415424176101 |
10 | 131132113300 |
11 | 50681728661 |
12 | 214b7a67784 |
13 | c49a5ba366 |
14 | 64bd9a7056 |
15 | 362743e76a |
hex | 1e88154194 |
131132113300 has 18 divisors (see below), whose sum is σ = 284556686078. Its totient is φ = 52452845280.
The previous prime is 131132113289. The next prime is 131132113337. The reversal of 131132113300 is 3311231131.
It can be written as a sum of positive squares in 3 ways, for example, as 538054416 + 130594058884 = 23196^2 + 361378^2 .
It is a super-2 number, since 2×1311321133002 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 655660467 + ... + 655660666.
Almost surely, 2131132113300 is an apocalyptic number.
131132113300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
131132113300 is an abundant number, since it is smaller than the sum of its proper divisors (153424572778).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
131132113300 is a wasteful number, since it uses less digits than its factorization.
131132113300 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1311321147 (or 1311321140 counting only the distinct ones).
The product of its (nonzero) digits is 162, while the sum is 19.
Adding to 131132113300 its reverse (3311231131), we get a palindrome (134443344431).
The spelling of 131132113300 in words is "one hundred thirty-one billion, one hundred thirty-two million, one hundred thirteen thousand, three hundred".
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