1311325401313 has 4 divisors (see below), whose sum is σ = 1312203718548. Its totient is φ = 1310447084080.

The previous prime is 1311325401311. The next prime is 1311325401341. The reversal of 1311325401313 is 3131045231131.

It is a happy number.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 928896946849 + 382428454464 = 963793^2 + 618408^2 .

It is a cyclic number.

It is not a de Polignac number, because 1311325401313 - 2¹ = 1311325401311 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1311325401311) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 439156378 + ... + 439159363.

It is an arithmetic number, because the mean of its divisors is an integer number (328050929637).

Almost surely, 2^{1311325401313} is an apocalyptic number.

It is an amenable number.

1311325401313 is a deficient number, since it is larger than the sum of its proper divisors (878317235).

1311325401313 is an equidigital number, since it uses as much as digits as its factorization.

1311325401313 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 878317234.

The product of its (nonzero) digits is 3240, while the sum is 28.

The spelling of 1311325401313 in words is "one trillion, three hundred eleven billion, three hundred twenty-five million, four hundred one thousand, three hundred thirteen".