131133100121 has 2 divisors, whose sum is σ = 131133100122. Its totient is φ = 131133100120.

The previous prime is 131133100069. The next prime is 131133100123. The reversal of 131133100121 is 121001331131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 126825015625 + 4308084496 = 356125^2 + 65636^2 .

It is an emirp because it is prime and its reverse (121001331131) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 131133100121 - 2¹⁸ = 131132837977 is a prime.

It is a Sophie Germain prime.

Together with 131133100123, it forms a pair of twin primes.

It is a Chen prime.

It is a Curzon number.

It is a self number, because there is not a number n which added to its sum of digits gives 131133100121.

It is not a weakly prime, because it can be changed into another prime (131133100123) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65566550060 + 65566550061.

It is an arithmetic number, because the mean of its divisors is an integer number (65566550061).

Almost surely, 2^131133100121 is an apocalyptic number.

It is an amenable number.

131133100121 is a deficient number, since it is larger than the sum of its proper divisors (1).

131133100121 is an equidigital number, since it uses as much as digits as its factorization.

131133100121 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 54, while the sum is 17.

Adding to 131133100121 its reverse (121001331131), we get a palindrome (252134431252).

The spelling of 131133100121 in words is "one hundred thirty-one billion, one hundred thirty-three million, one hundred thousand, one hundred twenty-one".