Base | Representation |
---|---|
bin | 111101000100000100… |
… | …1001100110101000111 |
3 | 110112110220010022122111 |
4 | 1322020021030311013 |
5 | 4122030040211403 |
6 | 140124114041451 |
7 | 12321413142331 |
oct | 1721011146507 |
9 | 415426108574 |
10 | 131133132103 |
11 | 50682264046 |
12 | 214b8279287 |
13 | c49a885cbc |
14 | 64bdb90451 |
15 | 362759156d |
hex | 1e8824cd47 |
131133132103 has 4 divisors (see below), whose sum is σ = 131249283040. Its totient is φ = 131016981168.
The previous prime is 131133132079. The next prime is 131133132107. The reversal of 131133132103 is 301231331131.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-131133132103 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (131133132107) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 58073775 + ... + 58076032.
It is an arithmetic number, because the mean of its divisors is an integer number (32812320760).
Almost surely, 2131133132103 is an apocalyptic number.
131133132103 is a deficient number, since it is larger than the sum of its proper divisors (116150937).
131133132103 is a wasteful number, since it uses less digits than its factorization.
131133132103 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 116150936.
The product of its (nonzero) digits is 486, while the sum is 22.
Adding to 131133132103 its reverse (301231331131), we get a palindrome (432364463234).
The spelling of 131133132103 in words is "one hundred thirty-one billion, one hundred thirty-three million, one hundred thirty-two thousand, one hundred three".
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