13113320111 has 4 divisors (see below), whose sum is σ = 13113744000. Its totient is φ = 13112896224.

The previous prime is 13113320093. The next prime is 13113320149. The reversal of 13113320111 is 11102331131.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 11102331131 = 71 ⋅156370861.

It is a cyclic number.

It is not a de Polignac number, because 13113320111 - 2¹⁴ = 13113303727 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 13113320111.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13113320411) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 161546 + ... + 228743.

It is an arithmetic number, because the mean of its divisors is an integer number (3278436000).

Almost surely, 2^13113320111 is an apocalyptic number.

13113320111 is a deficient number, since it is larger than the sum of its proper divisors (423889).

13113320111 is an equidigital number, since it uses as much as digits as its factorization.

13113320111 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 423888.

The product of its (nonzero) digits is 54, while the sum is 17.

Adding to 13113320111 its reverse (11102331131), we get a palindrome (24215651242).

The spelling of 13113320111 in words is "thirteen billion, one hundred thirteen million, three hundred twenty thousand, one hundred eleven".