Base | Representation |
---|---|
bin | 1011111011010010111101… |
… | …1100101011000011001011 |
3 | 1201102121210121011000020212 |
4 | 2332310233130223003023 |
5 | 3204322100241401303 |
6 | 43520103045311335 |
7 | 2522256400041653 |
oct | 276645734530313 |
9 | 51377717130225 |
10 | 13113331200203 |
11 | 41a6372664923 |
12 | 157955010554b |
13 | 74177436c9b0 |
14 | 33498d7c7363 |
15 | 17b193e46ad8 |
hex | bed2f72b0cb |
13113331200203 has 8 divisors (see below), whose sum is σ = 14122287733008. Its totient is φ = 12104408774304.
The previous prime is 13113331200191. The next prime is 13113331200217. The reversal of 13113331200203 is 30200213331131.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 13113331200203 - 210 = 13113331199179 is a prime.
It is not an unprimeable number, because it can be changed into a prime (13113331200223) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 7725401 + ... + 9268682.
It is an arithmetic number, because the mean of its divisors is an integer number (1765285966626).
Almost surely, 213113331200203 is an apocalyptic number.
13113331200203 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
13113331200203 is a deficient number, since it is larger than the sum of its proper divisors (1008956532805).
13113331200203 is a wasteful number, since it uses less digits than its factorization.
13113331200203 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 17053453.
The product of its (nonzero) digits is 972, while the sum is 23.
Adding to 13113331200203 its reverse (30200213331131), we get a palindrome (43313544531334).
The spelling of 13113331200203 in words is "thirteen trillion, one hundred thirteen billion, three hundred thirty-one million, two hundred thousand, two hundred three".
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