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131134424303 = 1131160481631
BaseRepresentation
bin111101000100000111…
…0001000010011101111
3110112110222112222012202
41322020032020103233
54122030403034203
6140124201452115
712321430133561
oct1721016102357
9415428488182
10131134424303
1150682a66983
12214b87a103b
13c49ac1920c
1464c0009331
153627749388
hex1e883884ef

131134424303 has 4 divisors (see below), whose sum is σ = 132294906048. Its totient is φ = 129973942560.

The previous prime is 131134424263. The next prime is 131134424357. The reversal of 131134424303 is 303424431131.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 131134424303 - 210 = 131134423279 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (131134424383) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 580240703 + ... + 580240928.

It is an arithmetic number, because the mean of its divisors is an integer number (33073726512).

Almost surely, 2131134424303 is an apocalyptic number.

131134424303 is a deficient number, since it is larger than the sum of its proper divisors (1160481745).

131134424303 is a wasteful number, since it uses less digits than its factorization.

131134424303 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1160481744.

The product of its (nonzero) digits is 10368, while the sum is 29.

Adding to 131134424303 its reverse (303424431131), we get a palindrome (434558855434).

The spelling of 131134424303 in words is "one hundred thirty-one billion, one hundred thirty-four million, four hundred twenty-four thousand, three hundred three".

Divisors: 1 113 1160481631 131134424303