131134505154335 has 4 divisors (see below), whose sum is σ = 157361406185208. Its totient is φ = 104907604123464.

The previous prime is 131134505154281. The next prime is 131134505154361. The reversal of 131134505154335 is 533451505431131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 131134505154335 - 2²⁴ = 131134488377119 is a prime.

It is a super-3 number, since 3×131134505154335³ (a number of 43 digits) contains 333 as substring.

It is a Duffinian number.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 13113450515429 + ... + 13113450515438.

It is an arithmetic number, because the mean of its divisors is an integer number (39340351546302).

Almost surely, 2^{131134505154335} is an apocalyptic number.

131134505154335 is a deficient number, since it is larger than the sum of its proper divisors (26226901030873).

131134505154335 is an equidigital number, since it uses as much as digits as its factorization.

131134505154335 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 26226901030872.

The product of its (nonzero) digits is 810000, while the sum is 44.

The spelling of 131134505154335 in words is "one hundred thirty-one trillion, one hundred thirty-four billion, five hundred five million, one hundred fifty-four thousand, three hundred thirty-five".