Base | Representation |
---|---|
bin | 1011111011010101100110… |
… | …1101000010010110100110 |
3 | 1201102200122000010112021020 |
4 | 2332311121231002112212 |
5 | 3204330023233224110 |
6 | 43520301252232010 |
7 | 2522313065626344 |
oct | 276653155022646 |
9 | 51380560115236 |
10 | 13114040133030 |
11 | 41a66a6855621 |
12 | 157970960b606 |
13 | 7418581b8c85 |
14 | 334a19a08994 |
15 | 17b1d62d0d70 |
hex | bed59b425a6 |
13114040133030 has 32 divisors (see below), whose sum is σ = 32143349435904. Its totient is φ = 3422671466976.
The previous prime is 13114040133013. The next prime is 13114040133037. The reversal of 13114040133030 is 3033104041131.
It is a super-2 number, since 2×131140401330302 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13114040133037) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 4650367432 + ... + 4650370251.
It is an arithmetic number, because the mean of its divisors is an integer number (1004479669872).
Almost surely, 213114040133030 is an apocalyptic number.
13114040133030 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
13114040133030 is an abundant number, since it is smaller than the sum of its proper divisors (19029309302874).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13114040133030 is a wasteful number, since it uses less digits than its factorization.
13114040133030 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 9300737740.
The product of its (nonzero) digits is 1296, while the sum is 24.
Adding to 13114040133030 its reverse (3033104041131), we get a palindrome (16147144174161).
The spelling of 13114040133030 in words is "thirteen trillion, one hundred fourteen billion, forty million, one hundred thirty-three thousand, thirty".
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