13114104101 has 4 divisors (see below), whose sum is σ = 14987547552. Its totient is φ = 11240660652.

The previous prime is 13114104089. The next prime is 13114104119. The reversal of 13114104101 is 10140141131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 10140141131 = 29 ⋅349660039.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13114104101 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 13114104101.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13114104151) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 936721715 + ... + 936721728.

It is an arithmetic number, because the mean of its divisors is an integer number (3746886888).

Almost surely, 2^13114104101 is an apocalyptic number.

It is an amenable number.

13114104101 is a deficient number, since it is larger than the sum of its proper divisors (1873443451).

13114104101 is an equidigital number, since it uses as much as digits as its factorization.

13114104101 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1873443450.

The product of its (nonzero) digits is 48, while the sum is 17.

Adding to 13114104101 its reverse (10140141131), we get a palindrome (23254245232).

The spelling of 13114104101 in words is "thirteen billion, one hundred fourteen million, one hundred four thousand, one hundred one".