13114111120021 has 4 divisors (see below), whose sum is σ = 13433967488844. Its totient is φ = 12794254751200.

The previous prime is 13114111119961. The next prime is 13114111120031. The reversal of 13114111120021 is 12002111141131.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 4173383208996 + 8940727911025 = 2042886^2 + 2990105^2 .

It is a cyclic number.

It is not a de Polignac number, because 13114111120021 - 2²⁹ = 13113574249109 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13114111120031) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 159928184350 + ... + 159928184431.

It is an arithmetic number, because the mean of its divisors is an integer number (3358491872211).

Almost surely, 2^{13114111120021} is an apocalyptic number.

It is an amenable number.

13114111120021 is a deficient number, since it is larger than the sum of its proper divisors (319856368823).

13114111120021 is an equidigital number, since it uses as much as digits as its factorization.

13114111120021 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 319856368822.

The product of its (nonzero) digits is 48, while the sum is 19.

Adding to 13114111120021 its reverse (12002111141131), we get a palindrome (25116222261152).

The spelling of 13114111120021 in words is "thirteen trillion, one hundred fourteen billion, one hundred eleven million, one hundred twenty thousand, twenty-one".