13114111120031 has 2 divisors, whose sum is σ = 13114111120032. Its totient is φ = 13114111120030.

The previous prime is 13114111119961. The next prime is 13114111120063. The reversal of 13114111120031 is 13002111141131.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13114111120031 is a prime.

It is a super-2 number, since 2×13114111120031² (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 13114111119985 and 13114111120012.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13114111122031) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6557055560015 + 6557055560016.

It is an arithmetic number, because the mean of its divisors is an integer number (6557055560016).

Almost surely, 2^{13114111120031} is an apocalyptic number.

13114111120031 is a deficient number, since it is larger than the sum of its proper divisors (1).

13114111120031 is an equidigital number, since it uses as much as digits as its factorization.

13114111120031 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 72, while the sum is 20.

Adding to 13114111120031 its reverse (13002111141131), we get a palindrome (26116222261162).

The spelling of 13114111120031 in words is "thirteen trillion, one hundred fourteen billion, one hundred eleven million, one hundred twenty thousand, thirty-one".