131141111334440 has 32 divisors (see below), whose sum is σ = 295067830860000. Its totient is φ = 52456385803584.

The previous prime is 131141111334253. The next prime is 131141111334451. The reversal of 131141111334440 is 44433111141131.

It is a super-2 number, since 2×131141111334440² (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 131141111334397 and 131141111334406.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 60354011 + ... + 62489109.

It is an arithmetic number, because the mean of its divisors is an integer number (9220869714375).

Almost surely, 2^{131141111334440} is an apocalyptic number.

131141111334440 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

131141111334440 is an abundant number, since it is smaller than the sum of its proper divisors (163926719525560).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

131141111334440 is a wasteful number, since it uses less digits than its factorization.

131141111334440 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3670649 (or 3670645 counting only the distinct ones).

The product of its (nonzero) digits is 6912, while the sum is 32.

Adding to 131141111334440 its reverse (44433111141131), we get a palindrome (175574222475571).

The spelling of 131141111334440 in words is "one hundred thirty-one trillion, one hundred forty-one billion, one hundred eleven million, three hundred thirty-four thousand, four hundred forty".