Base | Representation |
---|---|
bin | 11101110100010110101011… |
… | …011001110010000001110111 |
3 | 122012022222010120202200210121 |
4 | 131310112223121302001313 |
5 | 114142103444200024343 |
6 | 1142525221210432411 |
7 | 36423430003464544 |
oct | 3564265331620167 |
9 | 565288116680717 |
10 | 131141112111223 |
11 | 388706a6a43945 |
12 | 12860039132707 |
13 | 5823727944196 |
14 | 2455399805bcb |
15 | 10264344aaaed |
hex | 7745ab672077 |
131141112111223 has 2 divisors, whose sum is σ = 131141112111224. Its totient is φ = 131141112111222.
The previous prime is 131141112111209. The next prime is 131141112111241. The reversal of 131141112111223 is 322111211141131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 131141112111223 - 29 = 131141112110711 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131141112111263) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65570556055611 + 65570556055612.
It is an arithmetic number, because the mean of its divisors is an integer number (65570556055612).
Almost surely, 2131141112111223 is an apocalyptic number.
131141112111223 is a deficient number, since it is larger than the sum of its proper divisors (1).
131141112111223 is an equidigital number, since it uses as much as digits as its factorization.
131141112111223 is an evil number, because the sum of its binary digits is even.
The product of its digits is 288, while the sum is 25.
Adding to 131141112111223 its reverse (322111211141131), we get a palindrome (453252323252354).
The spelling of 131141112111223 in words is "one hundred thirty-one trillion, one hundred forty-one billion, one hundred twelve million, one hundred eleven thousand, two hundred twenty-three".
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