13114111430000 has 200 divisors, whose sum is σ = 36295767636480. Its totient is φ = 4495102560000.

The previous prime is 13114111429933. The next prime is 13114111430003. The reversal of 13114111430000 is 3411141131.

It is a tau number, because it is divible by the number of its divisors (200).

It is a Harshad number since it is a multiple of its sum of digits (20).

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13114111430003) by changing a digit.

It is a polite number, since it can be written in 39 ways as a sum of consecutive naturals, for example, 296147861 + ... + 296192139.

Almost surely, 2^{13114111430000} is an apocalyptic number.

13114111430000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 13114111430000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (18147883818240).

13114111430000 is an abundant number, since it is smaller than the sum of its proper divisors (23181656206480).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13114111430000 is an equidigital number, since it uses as much as digits as its factorization.

13114111430000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 48545 (or 48524 counting only the distinct ones).

The product of its (nonzero) digits is 144, while the sum is 20.

Adding to 13114111430000 its reverse (3411141131), we get a palindrome (13117522571131).

The spelling of 13114111430000 in words is "thirteen trillion, one hundred fourteen billion, one hundred eleven million, four hundred thirty thousand".