Base | Representation |
---|---|
bin | 1011111011010101110111… |
… | …1111001111000000001111 |
3 | 1201102200211000101101002112 |
4 | 2332311131333033000033 |
5 | 3204330200133343203 |
6 | 43520312341014235 |
7 | 2522314630611041 |
oct | 276653577170017 |
9 | 51380730341075 |
10 | 13114112012303 |
11 | 41a673338a585 |
12 | 15797296b437b |
13 | 74186a064ca3 |
14 | 334a25399a91 |
15 | 17b1dc77d6d8 |
hex | bed5dfcf00f |
13114112012303 has 4 divisors (see below), whose sum is σ = 13309845027480. Its totient is φ = 12918378997128.
The previous prime is 13114112012293. The next prime is 13114112012333. The reversal of 13114112012303 is 30321021141131.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 13114112012303 - 222 = 13114107817999 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13114112012333) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 97866507488 + ... + 97866507621.
It is an arithmetic number, because the mean of its divisors is an integer number (3327461256870).
Almost surely, 213114112012303 is an apocalyptic number.
13114112012303 is a deficient number, since it is larger than the sum of its proper divisors (195733015177).
13114112012303 is an equidigital number, since it uses as much as digits as its factorization.
13114112012303 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 195733015176.
The product of its (nonzero) digits is 432, while the sum is 23.
Adding to 13114112012303 its reverse (30321021141131), we get a palindrome (43435133153434).
The spelling of 13114112012303 in words is "thirteen trillion, one hundred fourteen billion, one hundred twelve million, twelve thousand, three hundred three".
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