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131141124034342 = 2174389699811241
BaseRepresentation
bin11101110100010110101100…
…000111010000111100100110
3122012022222011102012110020121
4131310112230013100330212
5114142104010223044332
61142525222314152154
736423430210024042
oct3564265407207446
9565288142173217
10131141124034342
1138870702747964
121286004112265a
13582372a25a196
14245539b22b022
151026435563797
hex7745ac1d0f26

131141124034342 has 16 divisors (see below), whose sum is σ = 213126751510992. Its totient is φ = 60278273153280.

The previous prime is 131141124034331. The next prime is 131141124034369. The reversal of 131141124034342 is 243430421141131.

It is a Harshad number since it is a multiple of its sum of digits (34).

It is a junction number, because it is equal to n+sod(n) for n = 131141124034298 and 131141124034307.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 44849904159 + ... + 44849907082.

It is an arithmetic number, because the mean of its divisors is an integer number (13320421969437).

Almost surely, 2131141124034342 is an apocalyptic number.

131141124034342 is a deficient number, since it is larger than the sum of its proper divisors (81985627476650).

131141124034342 is a wasteful number, since it uses less digits than its factorization.

131141124034342 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 89699811303.

The product of its (nonzero) digits is 27648, while the sum is 34.

Adding to 131141124034342 its reverse (243430421141131), we get a palindrome (374571545175473).

The spelling of 131141124034342 in words is "one hundred thirty-one trillion, one hundred forty-one billion, one hundred twenty-four million, thirty-four thousand, three hundred forty-two".

Divisors: 1 2 17 34 43 86 731 1462 89699811241 179399622482 1524896791097 3049793582194 3857091883363 7714183766726 65570562017171 131141124034342