Base | Representation |
---|---|
bin | 11101110100010110101100… |
… | …000111010000111100100110 |
3 | 122012022222011102012110020121 |
4 | 131310112230013100330212 |
5 | 114142104010223044332 |
6 | 1142525222314152154 |
7 | 36423430210024042 |
oct | 3564265407207446 |
9 | 565288142173217 |
10 | 131141124034342 |
11 | 38870702747964 |
12 | 1286004112265a |
13 | 582372a25a196 |
14 | 245539b22b022 |
15 | 1026435563797 |
hex | 7745ac1d0f26 |
131141124034342 has 16 divisors (see below), whose sum is σ = 213126751510992. Its totient is φ = 60278273153280.
The previous prime is 131141124034331. The next prime is 131141124034369. The reversal of 131141124034342 is 243430421141131.
It is a Harshad number since it is a multiple of its sum of digits (34).
It is a junction number, because it is equal to n+sod(n) for n = 131141124034298 and 131141124034307.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 44849904159 + ... + 44849907082.
It is an arithmetic number, because the mean of its divisors is an integer number (13320421969437).
Almost surely, 2131141124034342 is an apocalyptic number.
131141124034342 is a deficient number, since it is larger than the sum of its proper divisors (81985627476650).
131141124034342 is a wasteful number, since it uses less digits than its factorization.
131141124034342 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 89699811303.
The product of its (nonzero) digits is 27648, while the sum is 34.
Adding to 131141124034342 its reverse (243430421141131), we get a palindrome (374571545175473).
The spelling of 131141124034342 in words is "one hundred thirty-one trillion, one hundred forty-one billion, one hundred twenty-four million, thirty-four thousand, three hundred forty-two".
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