Search a number
-
+
13114114433 = 713913478021
BaseRepresentation
bin11000011011010100…
…11000000110000001
31020211221112001000222
430031222120012001
5203324203130213
610005144552425
7642660063530
oct141552300601
936757461028
1013114114433
11561a637302
12265ba82715
13130cc17a34
148c5992317
1551b493808
hex30da98181

13114114433 has 8 divisors (see below), whose sum is σ = 15095384640. Its totient is φ = 11159800560.

The previous prime is 13114114399. The next prime is 13114114477. The reversal of 13114114433 is 33441141131.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 13114114433 - 210 = 13114113409 is a prime.

It is a super-2 number, since 2×131141144332 (a number of 21 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (13114114933) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 6738038 + ... + 6739983.

It is an arithmetic number, because the mean of its divisors is an integer number (1886923080).

Almost surely, 213114114433 is an apocalyptic number.

It is an amenable number.

13114114433 is a deficient number, since it is larger than the sum of its proper divisors (1981270207).

13114114433 is a wasteful number, since it uses less digits than its factorization.

13114114433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 13478167.

The product of its digits is 1728, while the sum is 26.

Adding to 13114114433 its reverse (33441141131), we get a palindrome (46555255564).

The spelling of 13114114433 in words is "thirteen billion, one hundred fourteen million, one hundred fourteen thousand, four hundred thirty-three".

Divisors: 1 7 139 973 13478021 94346147 1873444919 13114114433