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13114120003 = 64679202757
BaseRepresentation
bin11000011011010100…
…11001011101000011
31020211221112022200021
430031222121131003
5203324203320003
610005145034311
7642660116005
oct141552313503
936757468607
1013114120003
11561a640506
12265ba85997
13130cc1a42a
148c5994375
1551b4952bd
hex30da99743

13114120003 has 4 divisors (see below), whose sum is σ = 13114387440. Its totient is φ = 13113852568.

The previous prime is 13114119913. The next prime is 13114120009. The reversal of 13114120003 is 30002141131.

13114120003 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 30002141131 = 130123060831.

It is a cyclic number.

It is not a de Polignac number, because 13114120003 - 213 = 13114111811 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13114120009) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 36700 + ... + 166057.

It is an arithmetic number, because the mean of its divisors is an integer number (3278596860).

Almost surely, 213114120003 is an apocalyptic number.

13114120003 is a deficient number, since it is larger than the sum of its proper divisors (267437).

13114120003 is an equidigital number, since it uses as much as digits as its factorization.

13114120003 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 267436.

The product of its (nonzero) digits is 72, while the sum is 16.

Adding to 13114120003 its reverse (30002141131), we get a palindrome (43116261134).

The spelling of 13114120003 in words is "thirteen billion, one hundred fourteen million, one hundred twenty thousand, three".

Divisors: 1 64679 202757 13114120003