Base | Representation |
---|---|
bin | 1011111011010101111100… |
… | …1001000000100100001111 |
3 | 1201102200212100202220221001 |
4 | 2332311133021000210033 |
5 | 3204330220111224243 |
6 | 43520314311321131 |
7 | 2522315254156345 |
oct | 276653711004417 |
9 | 51380770686831 |
10 | 13114131351823 |
11 | 41a6743299657 |
12 | 15797340801a7 |
13 | 7418710768a8 |
14 | 334a27b91995 |
15 | 17b1de2eda4d |
hex | bed5f24090f |
13114131351823 has 2 divisors, whose sum is σ = 13114131351824. Its totient is φ = 13114131351822.
The previous prime is 13114131351803. The next prime is 13114131351829. The reversal of 13114131351823 is 32815313141131.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13114131351823 - 29 = 13114131351311 is a prime.
It is a super-2 number, since 2×131141313518232 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13114131351829) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6557065675911 + 6557065675912.
It is an arithmetic number, because the mean of its divisors is an integer number (6557065675912).
Almost surely, 213114131351823 is an apocalyptic number.
13114131351823 is a deficient number, since it is larger than the sum of its proper divisors (1).
13114131351823 is an equidigital number, since it uses as much as digits as its factorization.
13114131351823 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 25920, while the sum is 37.
Adding to 13114131351823 its reverse (32815313141131), we get a palindrome (45929444492954).
The spelling of 13114131351823 in words is "thirteen trillion, one hundred fourteen billion, one hundred thirty-one million, three hundred fifty-one thousand, eight hundred twenty-three".
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